Monday, January 30, 2012

Right Round the Lab!

Post Questions about the lab here!
This is the Link to the Page due on Friday! Centripetal Force 2012 - http://goo.gl/nsIo3

16 comments:

  1. Is a range of 2.5 seconds precise or two large of a deviation between shortest and longest trials?

    Max

    ReplyDelete
  2. Well, that depends. Is that the time for 20 swings? Or 1? Are your trials all for the same length and mass? The best way to check is to do your calculations and calculate a % error.

    ReplyDelete
  3. Okay, so for the link to put our data and calculations in, it asks for Ft (tension) and I know Mr. Crane said that Fc should = tension, so if our Fc is .26, should Ft be .26 as well?

    Also, for period (T), is it how many seconds it took for one rotation or is it the circumference of the circle?

    Thanks!

    ReplyDelete
  4. Period is the the time for 1 complete of anything and is a measurement of time.
    Circumferences measures distance.
    Fc=Fg=Ft. So which one can be relied upon to a higher degree of certainty Fc or Fg. Whichever you think is a more reliable measure of the Ft is the one you should put.

    ReplyDelete
  5. Because Fg is more concrete, should we use Fg as an estimator of the accuracy of Fc? Also, are we answering the lab questions in the packet for Friday as well? Thanks

    ReplyDelete
  6. so we use the circumference for the velocity, and the time for a single rotation?

    ReplyDelete
  7. what does a (centripetal) stand for on the website?

    ReplyDelete
  8. for the percent error, what value should be used for the theoretical and the actual?
    I used the mass of the stopper for the actual and mvsquared over r for the theoretical. Is that correct?
    Thanks

    ReplyDelete
  9. experimental is your Fc which is m(v)sq/r and Fg is theoretical which is the weight of the washers.

    ReplyDelete
  10. i have another question: if your percent error is <10%, do we have to write an explanation? and should the ac be the velocity of the trial you are using (sq) over the radius? thanks!

    ReplyDelete
  11. when you ask for "a (centripetal)", do you want an acceleration?

    ReplyDelete
    Replies
    1. isn't it just m(v)squared over the radius equals ma(centripetal) equals Fc. and use the Fc of the best trial?

      Delete
    2. so the Fc of your best trial is a (centripetal)

      Delete
  12. If he is askin for acceleration take out mass

    ReplyDelete

Tweets by @Physicsmainland