Notes from Period 7 2.27.13
In your notebook
Part 1
Watch the video below.
Top Gear - Ariel Atom - BBC http://www.youtube.com/watch?v=WaWoo82zNUA&sns=tw via @youtube
PUKES
HINT: BREAK THE problem into smaller picture wit proper starting and ending points.
Calculate the acceleration from 0-60mph.
Calculate the distance from 0-60mph.
Calculate the time from 0-100mph.
Calculate the time from 60-100mph.
Calculate the distance from 0-100mph.
Calculate the distance from 60-100mph.
Part 2
Watch video
0-100-0mph - the perfect run - by Autocar.co.uk http://www.youtube.com/watch?v=Cbo4mHIzQD0&sns=tw via @youtube
Draw a Picture only.
If a SQUIRELL is running across the street 15m wide at 5m/s. If you are driving 50 mph in an Ariel atom and see the SQUIRELL when it is 30m in front of the car. What happens? Explain using the picture what is going on.
Do we have to puke this?
ReplyDeleteJust the first video and only a picture for the second video.
ReplyDeleteSo I watched the first video, was I supposed to learn any variables for an equation or something? Can someone help me out, I don't quite understand how we should calculate the requirements.
ReplyDelete-Jake Naumann
I heard them say "0 to 60 in 2.9 seconds." I then found the acceleration and used that in all of the problems.
Delete-Kevin Meglathery
Kevin I the 0 to 60 in 2.9 seconds the acceleration I was a little confused.
DeleteI don't quite understand how to find acceleration. Would acceleration just be 60mi/hr/hr? 60mi per h^2?
DeleteJohn to find the acceleration I used the formula V= A x t + Vo
DeleteDid you then alter the equation so that A=^V/t(Change in V over t)?
DeleteAre we supposed to PUKE for each single thing or is it one giant PUKE in our books.
ReplyDeleteI puked for each video, not each individual problem.
Delete-Kevin Meglathery
I made one Puke but had sub-pukes underneath each category; like a b c d e f representing respective scenarios but all under the same general category (known unknown etc)
DeleteOne picture should suffice for each part, but the unknowns and equations change depending on what you're trying to figure out. I don't think you would have to re-PUKE everything, just write the equation you derived and solve for it.
DeleteThank you so much! It makes a lot more sense than the answers I was getting. For the 0-100 and 60-100, did you plug in the same number or did they mention another number? I would assume yo uwould use the same number.
ReplyDelete-Jake Naumann
I used the same numbers for every problem, and they seemed reasonable.
Delete-Kevin Meglathery
For the 60-100, I started with a starting velocity, due to the fact it is already in motion.
Delete~Thomas Black
Kevin, what did you get for the second question as your answer (also what was the fomula you used). I just want to see if I'm going in the correct direction.
Delete-Jake Naumann
That question was asking for distance (which I think is the same as P). I got 43.48m using the formula
DeleteP=1/2a(t squared)+(V-nought)(time)+starting position
-Kevin Meglathery
Thank you so very much! Ok I so the acceleration of 10.34 that I plugged in is the same as what you plugged in since we have the same answer.
Delete-Jake Naumann
Thomas, what did you have for the starting velocity for that then, since it's already in motion?
DeleteThe maximum velocity for 0-60.
Delete~Thomas Black
With the squirrel problem, does the squirrel start running 30m away from the car? Or is it in the middle of the street?
ReplyDelete-Kevin Meglathery
As long as you make clear of your starting point it should be fine.. it only says to draw a picture.
Delete-Jake Naumann
Can someone help me I am really confused. What equation do we use and is the 2.9 seconds the acceleration form 0 to 60 and do we use the same equation to find the distance as well.
ReplyDeleteI just used the equations in the back of our notebooks. 2.9 seconds is the time it takes to go from 0 to 60 mph. For the distance problems, I used P instead of distance.
Delete-Kevin Meglathery
I did a proportion - 60miles/3600seconds = x/2.9seconds
DeleteWould the proportion work though? Since it's accelerating, I don't think the distance traveled would be increasing at a constant rate (please correct me if I'm wrong).
DeleteCould you use the equation t equals the square root of 2 times the change in position divided by acceleration. Because we don't know velocity and acceleration is always the same and for change in position by how far apart 0 to60 is and 60 to 100. If you could correct me if I am wrong that would be greatly appreciated.
ReplyDeleteYou could use that equation. But remember that we already know the velocities.
DeleteStarting velocity is 0m/s
60 mph is 30m/s
100 mph is 50m/s
Therefore, you could use a different equation, but your approach seems fine.
-Kevin Meglathery
Now for "a" do we use 9.8 m/s^2?
Delete-Jake Naumann
Thank you so much Kevin that helps alot.
DeleteNo, a is not gravity. In this scenario, we don't have to worry about gravity. The acceleration that I got was 10.34 meters/s/s.
Delete-Kevin Meglathery
Yea I didn't mean to write 9.8 m/s^2... I realized after you commented.
Delete-Jake Naumann
This comment has been removed by the author.
ReplyDeleteI am so confused on how we are suppose to do this. can someone show me how they did the first one as an example please
ReplyDeleteWith what question?
DeleteLike the first one where it is ejaculation the acceleration from 0-60 mph
DeleteDid you watch the video? It is in there.
DeleteThe first one is asking for the acclereation. The video says that the Atom accelerates from 0 to 60 in 2.9 seconds. Now, you need to start puking. You're looking for "a" and you know time, starting velocity, and ending velocity. Now find an equation with those variables and solve.
Delete-Kevin Meglathery
What equation am i supposed to use?
DeleteWhat are you looking for.? Then find an equation that. Relates. What you have and what you are trying g to find.
Deleteso the equation you would use would be v=a x t + Vo and then you would plug everything in and solve for a, correct?
DeleteCan someone help me with the last distance one... 60-100... How do you set that problem up. Can you drop V nought times t and P nought, or is something filled in for them?
ReplyDelete-Jake Naumann
For that one, I used the 1/2at squared..... formula. You can't drop V-nought or P-nought because they have values now. Because it is asking for the distance between 60mph and 100mph, your starting velocity (V nought) is 30m/s. Your P nought is whatever you got for question 2.
Delete-Kevin Meglathery
Ok, thought so... Just making sure because I kept getting large answers and didn't know if they were correct.
Delete-Jake Naumann
For the last distance one you don't have to use the formula, although it still works well. Your trying to find the distance between the two points(the positions of which you found in the 2nd and 5th questions)in which the car is traveling 30 m/s (60 mph) and 50 m/s (100 mph). You simply are trying to find the change in position to get the distance. Since you calculated the positions, you can calculate the change in them to find the distance.
Delete-Billy Potts
for the acceleration from 0-60 can we just say that they told us?
ReplyDeleteBut they didn't tell you the acceleration they told you the information for you to calculate.
DeleteIs our A value still going to be -9.8 and not just 9.8? Can someone remind me why?
ReplyDeletewe don't know acceleration, that's what we are trying to find. You have to figure out and equation with those variables that were given.
DeleteIt's not going to be 9.8 because that's the acceleration of gravity. Gravity isn't impacting that motion in a way that we need to calculate it. You have to use one of the formulas we already have and derive the acceleration formula from it.
DeleteWhat would the picture look like for the first problem? A parabola?
ReplyDeleteThis comment has been removed by the author.
DeleteThis comment has been removed by the author.
DeleteHalf a parabola because it doesn't slow down, we are only looking from 0-x
Deletewhat would the final velocity be?
DeleteWhy do we need that?
DeleteI really don't understand the acceleration formula. What am i supposed to use? I keep getting 20.69, which doesnt seem right.
ReplyDeleteI got that too
DeleteMimi, remember that it should be in M/S. I have a feeling yours is in MPH. My answer for acceleration was 10.34 M/S which is = to 20.69 MPH, but I find it easier to put into M/S.
Delete-Jake Naumann
Can someone clarify on the Squirrel Problem in Part 2? I'm a little confused on what it's asking.
ReplyDeleteWill you hit the Squirrel?
Deletea=2P-t^2 ???
ReplyDeletewhat is this for? Aceeleration right? What would P be?
DeleteYeah, but wouldn't that only work when the starting velocity is 0? P is most likely the ending position.
DeleteFor the acceleration equation I got 2 times the Change in Position divided by time. Is that right?
DeleteThat is almost right. There is that equation, which would be 2(change)P / t^2, as long as V(naught)=0 and P(naught)=0. Then there is also (change)V/t=a. Mr. Crane probably already explained this though.
Deletethe p was supposed to be change in p
ReplyDeleteOnce you solve for acceleration, it is the same for every problem right? it doesn't change for each different question?
ReplyDeleteYou're correct, use the same A value in each problem.
Delete-Jake Naumann
Jake, I saw that you and Kevin had the same acceleration of 10.34, but I got 17.39. Can you explain what formula you got to solve for it?
DeleteNazia,to find out the acceleration for the first one you must turn the 60 mph into 30 m/s. Since they equal the same (note in your book that 2 x m/s = mph. once you have 30 m/s, you need to divide it by 2.9... In the video they said it takes 2.9s for the car to go from 0-60. Once you are done all of that you should get 10.34 m/s^2
Delete-Jake Naumann
Sorry about that... forgot the fomula, I used the basic a= d(distance) divided by t if you were wondering.
Delete-Jake Naumann
Jake, what did you use for distance in that formula?
Delete-Robyn K.
Not saying that we do know any other easier equations, but could we use any equation with the same variables, and just use algebra to switch it around to find what we want?
ReplyDelete~Mike Keough
Yeah. If we know "a", "b", and "c" and are trying to find "d", then we just have to find an equation with those variables. From there, just isolate your unknown. Mr. Crane told us in class that the P=1/2at.... equation is really 5 equations in one, one for each variable.
Delete-Kevin Meglathery
Surely, just a matter of whether or not which equation is easiest to use, and whether or not it has the right variables.
Delete~Thomas Black
I'm confused so for the Part 1, let's say after we find the acceleration the car travels in then do we apply that answer to continue with the next problem. So basically we would be applying that "P+C" Method, right?
ReplyDelete-Jessica P period3
Yes, you do. Each answer that you get helps you solve another problem.
Delete-Kevin Meglathery
You're basically starting with one variable, and as you progress through the problems, you keep applying what you know and what you've already calculated.
DeleteOkay,so for part 2, after drawing the squirrel picture, should we be stating obvious? As the cars/squirrels acceleration, speed, time, Po, P,etc.. and should that be calculated or measured?
ReplyDeleteI believe you can calculate it. You dont have to do all of PUKES for that you only need to find the answer after you draw the picture.
DeleteThe answers i am getting for number three dont make sense. Could some one explain to me how to get the time?
ReplyDeleteWell, the first thing you should do is decide what your unknown is, which is time. Then you list the variables that you already know from the video or calculating it before. Using those variables, you have to figure out which equation would work best. In this case, it would be change in time equals change in velocity divided by acceleration. Plug in and solve! You could also use your picture and make a close estimate as well.
DeleteFor number 3 does it mean that the car tries to stop? Or does it just keep going and so does the squirrel?
ReplyDelete-Nick Giunta
Yes the car is going to stop so what is the stopping time ?
ReplyDeleteFor the distance 60-100 what would you do?
ReplyDeletehow do you find distance? what formula are we supposed to use? im still a little confused
ReplyDelete-gianna b.
Gianna there are several formulas you can use to find distance. I used D= 1/2at^2
Delete-Stefania T.
Could someone clarify what we have to do for the last one where we are finding the distance from 60-100 mph? I'm confused
ReplyDelete-Stefania Tutra
It's asking for the distance you travel as you accelerate from 60 to 100 mph. So instead of using 0 for V nought, just use 30m/s.
Delete-Kevin Meglathery
Or use the positions at 30 m/s and 50 m/s already calculated to find the change in position a.k.a distance (Unless its negative as distance ignores direction), which you could also use the formula to find.
Delete-Billy Potts
What time in the first video does the guy say it goes from 0-60 in 2.9 seconds? Did he say 0-60 miles per hour? Did he use miles even though he is British? Sorry that I asked so many things in one comment!
ReplyDelete-Robyn Kimmel
He did say 60 miles per hour. I don't remember the exact time in the video, but it is 2.9 seconds.
Delete-Kevin Meglathery
Do we measure distance in miles?
ReplyDelete-Robyn Kimmel
Do we use meters or miles? All of the Ms are confusing me!
Delete-Robyn K.
We should be using meters. Remember that all you need to do to get from mph to m/s is divide by two.
Delete-Kevin Meglathery
Remember the MKS System! They're the fundamentals of Physics that we'll be using the most, so thy're the units that our answers should be in: meters, kilograms, seconds.
DeleteWhere in the street do I spot the squirrel?
ReplyDelete-Robyn K.
It doesn't really matter where, just as long as you state its starting position.
Delete-Kevin Meglathery
When we PUKE should we always use equations from the back of our books?
ReplyDeleteYes always find the equation that fits all of the variables, the formulas will always work, but you may need to think about which one you use depending on what you are looking for...
Delete-Jake Naumann
Sam you should always use the equations from your notebook. For the quiz he said he is giving us the equations or he is allowing us to use our notebooks. Just make sure you have all of them down in case you get to use your notebook.
DeleteHow do you calculate the time from 0-100mph?
ReplyDeleteStart "puking" the problem. Write your knowns (V nought, V, accelaration) and then find an equation which you can use to find what you're looking for. You can use the equation V=at+V nought, which you can algebraically change to t=change in V/A. After that it just becomes a plug in problem.
Delete-Stefania T.
Thanks Stefania! This helped me a lot (:
Delete-Catherine Samara
Thanks!
ReplyDelete~Molly Lawlor
Will this subject and/or the squirrel problem appear on tomorrow's quest?
ReplyDeleteI think something similar to it will be. Considering we had to find the unknown and plug and chug.
Delete-Catherine Samara
Yeah, as long as you understand how to use PUKES to solve the problem, you should be fine for tomorrow's quiz. I'm guessing that the questions will ask you to find one thing, and then you use that one thing to solve for other variables, like we did for the Ariel Atom.
DeleteQuiz today . . . I'm a bit antsy about that, and I have a feeling some other students are too.
ReplyDeletehttp://www.youtube.com/watch?v=D5rNKUdMNfE
This reminded me of the Ariel Atom hitting the cute little squirrel.
Loosen up kids, things could be worse.
Posting from my phone just thought I'd share since it seems to be an issue. There's a Blogger app on Android FYI I'm sure there's one for the iPhone too. Hope this helps solve the problem!
ReplyDeleteFor the squirrel problem, how would we determine the fate of the squirrel? I know that we can find the deceleration, stopping distance, and stopping time, but how would we use those in the problem? We don't know exactly where the Atom is on the road or how wide the deadly part of the car is. Any input?
ReplyDelete-Kevin Meglathery
The stopping distance. Less than 30 meters, squirrel lives.
DeleteMore than 30 meters, the car either hits the squirrel or the squirrel gets out of the way first. That is when you would to see if the squirrel gets out of the way using your picture(and equations).
If you need to assume after that to determine the fate of the squirrel (you should't need to), I would assume standard lane widths as they say the car can be driven on roads. It can't be bigger than the road lane it is in.
-Billy Potts
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