I believe you are finding v nought, so your velocity is you change in Position divided by time. a=9.8. Use the 2nd equation I wrote to figure out your v nought.
V-Initial and V are both the same thing because what goes up must come down at the same speed in the opposite direction in the same amount of time. So you could just use V = at.
To find the Jumping Velocity? It's not the change in position one because the variables that you need when finding the velocity are acceleration and time.
I was absent too. It was what we did in class today basically. We had to find an equation for jumping velocity. So i dont think you have to do anything except what the homework tonight is.
Basically, yes. You look through the equations that we discovered in class from previous labs and decide which one would be the best one to find velocity. That's where PUKES comes in. Your unknown is V or V-initial, and your knowns are acceleration and time. The equation we derived was V = at.
We had to use the equation with change in position equalling 1/2at squared plus v nought times time plus p nought. I believe we are looking for p nought so you have to get that by itself to figure it out.
The ones we had to grab at the end off class. Rich on Monday go to the library and i will show you. They are titled chapter 3 linear motion-free fall speed and chapeter 3 linear motion-acceleration fo free fall
Are we supposed to just do the PUKES write up for #2 of the free fall part of the worksheet or does he want us to finish the rest of the questions? He didn't get a chance to explain since the bell rang and we were all over the place.
Does anyone know how to do this?
ReplyDeleteI took the equation V=a•t+Vnought and made it Vnought=a•t+V and figured it out from there I am not sure if that is correct though
ReplyDeletei understand what you are doing, but wouldn't the equation then be -Vnought=a*t-V? it would have changed becuase you would have changed it around?
DeleteSo v nought would be 0 acceleration would be 9.8 ad you use your time from hang time but what would velocity be?
ReplyDeleteI believe you are finding v nought, so your velocity is you change in Position divided by time. a=9.8. Use the 2nd equation I wrote to figure out your v nought.
ReplyDeleteV-Initial and V are both the same thing because what goes up must come down at the same speed in the opposite direction in the same amount of time. So you could just use V = at.
DeleteOk thanks are you still using the time that you found in hang time!
ReplyDeleteWould the unit be meters over seconds or meters over seconds over seconds
ReplyDeleteThe only thing that would be meters over seconds over seconds would be the 9.8 m/s²
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ReplyDeleteDoes anyone know if the equation we are supposed to use for homework tonight is the change in position one? I forgot to write it down.
ReplyDeleteTo find the Jumping Velocity? It's not the change in position one because the variables that you need when finding the velocity are acceleration and time.
DeleteWhat is this assignment? I was absent yesterday but noticed it was a grade on PowerSchool. Can someone please explain this assignment?
ReplyDeleteI was absent too. It was what we did in class today basically. We had to find an equation for jumping velocity. So i dont think you have to do anything except what the homework tonight is.
DeleteWas this just calculating the velocity
ReplyDeleteBasically, yes. You look through the equations that we discovered in class from previous labs and decide which one would be the best one to find velocity. That's where PUKES comes in. Your unknown is V or V-initial, and your knowns are acceleration and time. The equation we derived was V = at.
DeleteWe had to use the equation with change in position equalling 1/2at squared plus v nought times time plus p nought. I believe we are looking for p nought so you have to get that by itself to figure it out.
ReplyDeleteTo find your jumping velocity you have to find V naught.
Delete-Billy Potts
Was our hw the two work sheets we got in class?
ReplyDeleteWe only had to do certain numbers. The worksheet with the speed-ometer we had to fill them in.
Delete-James Gallagher
What two sheets?
ReplyDeleteThey should have been the two weorksheets that Mr.Crane handed out last week. One has a colum of speed-ometers.
Delete-James Gallagher
The ones we had to grab at the end off class. Rich on Monday go to the library and i will show you. They are titled chapter 3 linear motion-free fall speed and chapeter 3 linear motion-acceleration fo free fall
ReplyDeleteMr. Crane, how are you supposed to solve for the Free Fall Distance part of the worksheet?
ReplyDeleteAre we supposed to just do the PUKES write up for #2 of the free fall part of the worksheet or does he want us to finish the rest of the questions? He didn't get a chance to explain since the bell rang and we were all over the place.
Delete