I got a V of 8.32m/s for #3 by using P/M1+M2=V Joe R
i also got 8.32 m/sthe combined masses are 250 kg, divide the momentum by 250 to cancel kg which leaves you with 8.32 m/s(2080/250)=V
For this one, I got 250 m/s. Again, I multiplied 2.08 by 10^4 and got 20800, NOT 2080.
i got 83.2 m/s im not sure where i added on the extra zero in the problem.
you're right! it is 83.2 i lost a zero it should be 20800. for my other one i also lost a zero when writing it but the answer was still correct
#4 I used P/M=V to get 7930.62m/s Joe R
i also got this. (66300 kg(m/s)) / 83.6 kg = 7930.62 m/s, kilograms cancel.
For number 4, is it 6.63 x 10^3? Because if it is, then I think you guys are off. I divided 6630 by 83.6 KG and got 79.3 m/s
John, they saw 10^5 which is why the decimal is off
for question four is it 10^3 or 10^5 it is to small for me to read
I think 5, it just changes the answer a couple of decimal places
Do we just take equations like p = MV and plug in numbers for each equation to solve- Haley Krachman
yep, but sometimes mass was split into two separate things but it seems pretty basic
is this all we're doing with momentum? it's so simple. . .seems too good to be true
When will we find out our lab grades? -Jess Higbee
It is simple, for now
I got a V of 8.32m/s for #3 by using P/M1+M2=V
ReplyDeleteJoe R
i also got 8.32 m/s
Deletethe combined masses are 250 kg, divide the momentum by 250 to cancel kg which leaves you with 8.32 m/s
(2080/250)=V
For this one, I got 250 m/s. Again, I multiplied 2.08 by 10^4 and got 20800, NOT 2080.
Deletei got 83.2 m/s im not sure where i added on the extra zero in the problem.
Deleteyou're right! it is 83.2 i lost a zero it should be 20800. for my other one i also lost a zero when writing it but the answer was still correct
Delete#4 I used P/M=V to get 7930.62m/s
ReplyDeleteJoe R
i also got this. (66300 kg(m/s)) / 83.6 kg = 7930.62 m/s, kilograms cancel.
DeleteFor number 4, is it 6.63 x 10^3? Because if it is, then I think you guys are off. I divided 6630 by 83.6 KG and got 79.3 m/s
DeleteJohn, they saw 10^5 which is why the decimal is off
Deletefor question four is it 10^3 or 10^5 it is to small for me to read
ReplyDeleteI think 5, it just changes the answer a couple of decimal places
DeleteDo we just take equations like p = MV and plug in numbers for each equation to solve
ReplyDelete- Haley Krachman
yep, but sometimes mass was split into two separate things but it seems pretty basic
Deleteis this all we're doing with momentum? it's so simple. . .seems too good to be true
ReplyDeleteWhen will we find out our lab grades? -Jess Higbee
ReplyDeleteIt is simple, for now
ReplyDeleteIt is simple, for now
ReplyDelete