This is paramount to your success. If you can not find time to do this you really do not want to be in Physics B. I can. Not stress this enough. It is like working out for you to reap any benefit you must push yourself as hard as possible. It will be difficult at times but that's when you know it's working!
You may and should discuss questions you have here on the blog. Be sure to include the question # and the issue you are having.
Assignment details.
- All problems should be done in a composition notebook with the first 5 pages left blank for T.O.C.
- Each entry work date should be note with start and end times with your name in the upper right hand corner---->. First initial and last name is acceptable.
- Answers are to be recorded on google form.
- You Should be devoting a minimum of 2 hours a week to this or 5 problems a day. If you work for 2 hrs and get all the problems done Great.
What do you mean by "anwsers are to be recorded in google form"?
ReplyDeleteSorry Noah. There will be a link to a FORM where you can input your answers to the questions.
ReplyDeleteI can't see any of the images on my computer or on my phone. Will this prevent me from answering any of the problems?
ReplyDelete-Kevin Meglathery
Will check into that...
DeleteUsing Mozilla Firefox version 21. I will try to make the files and code as friendly as possible but my default browser is Firefox.
DeleteWhen is this due?
ReplyDeleteIt will be posted. End of July.... Ish
DeleteAre we supposed to just complete this or blog about it also?
ReplyDeleteBlog about it if you have questions or see that someone else has questions. It' never hurts to do a little blogging.
ReplyDelete-Hope Greenspun
Are there going to be multiple sets of questions like this, or will this be it for the summer?
ReplyDeletewould you like this to be done in our notebook? and if so should we right out the questions and show work or should we just right the answers?
ReplyDelete~All problems should be done in a composition notebook with the first 5 pages left blank for T.O.C.
Delete~Each entry work date should be note with start and end times with your name in the upper right hand corner---->. First initial and last name is acceptable.
I suggest writing out the answers, Kara. That way, when school comes around, you'll be able to recall how you got your answer to each problem.
is the link to the form on google for our answers to be recorded posted?
ReplyDeletewtf
ReplyDeleteWhat does question 17 say?
ReplyDeleteI also can't see any images.
I'm using Google Chrome, Internet Explorer or Mozilla Firefox 22.
*and
DeleteI can't see any images either, so I have to skip a lot of them. I don't know what I can do but I'll do everything else
ReplyDeleteis there anyone besides me that can see the images?
ReplyDeleteAlso if you are having an issue you need to post your browser/OS versions. Read the blog the info is currently being viewed using Firefox on a c not an iPhone mobile device...
ReplyDeleteI'm using Firefox, not sure what version so it might be pretty old. I can't get the pictures here or on my tablet using google chrome. I also can't see what question 17 says.
ReplyDelete-Jason Rodman
For anyone that cannot see the pictures, I used this site
ReplyDeletehttp://staff.orecity.k12.or.us/les.sitton/Chapter%202/Problems.htm
-Kathleen Popa
Thanks
DeleteBoth Internet Explorer and Firefox on my computer do not show any images. I just installed Firefox a few weeks ago, so that should be up to date. Im not really sure about Internet Explorer though.
ReplyDelete-Kevin Meglathery
Here is a link to a PDF. You must have adobe acrobat reader or equivalent installed.
ReplyDeletehttps://dl.dropboxusercontent.com/u/13300434/AP%20Online%20Problem%20Sets/Ch.2%201D%20Kimnematics%20Problems.pdf
For 40, I don't understand what to do and for 61 there isn't any sort of parabolic curve and so I don't know how to calculate its acceleration. It's like it has sudden changes in velocity but the acceleration isn't a constant in any segment so I put zero but that worries me because it does change velocity so wouldn't it have to accelerate at some point?
ReplyDeleteJon- I just came on to ask about 40 too because I did not think there was enough information but if you click on the link Mr. Crane just posted it has a picture for the problem, that I didn't see before, that gives the times which then makes it easily solvable with the equation d=(1/2)at^2, and make sure you have all the same units. That helped me, hope it works for you too!
DeleteThsnks Mare! I had seen the picture I just didn't understand it but thanks!
DeleteThe PDF works
ReplyDeleteHow do you do #30 without guess and check? Is there a formula that you can use?
ReplyDeleteSince both time and the final position are the same for both of them, you know P naught of both, and each of their accelerations, and V naught=0 for both, you can use the formula t=Square Root((2*delta P)/(a)) and since t=t, get:
DeleteSquare Root((2*delta P)/(a))=Square Root((2*delta P)/(a))
[Sir George] [Sir Alfred]
After that you plug in the numbers and solve for the final position (the same for both so there is only one variable in the equation). Watch the negatives because they matter.
Remember the positions, accelerations, etc. are relative to Sir George.
Also:
delta P=Change in P=Pf-Pnaught
Thanks Billy
DeleteIn #35, is the starting velocity supposed to be assumed as 0?
ReplyDeleteNo. You need to draw a picture. It should have 2 parts. The key is that what ever its doing at the end of part one is what it is doing at the beginning of part 2.
ReplyDeleteOk, I got it. Thanks.
DeleteDoes anybody know how to turn this in?
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteI am guessing you figured this out.
ReplyDeleteI'm not sure if this is just my computer or if this is the same for everybody but I can't seem to find any links to turn this assignment in. I'm hoping it wasn't posted yet but could someone please help?
ReplyDelete-Jason Rodman
I believe you are correct, there do not seem to be any submit links on the blog. Maybe it's just both of our computers, but I doubt it.
Delete-Kevin Meglathery
Can anybody offer any help for number 12?
ReplyDeletei found that it takes 2/3 of a second for the wall to travel the 2 meters of the width of the window, but i can't figure out how long it would take for the wall to travel the .9 meters of the height of the window? and when you find that number the answer is just the higher of the two, correct?