Objectives
After studying the material of this chapter, you should be able to:1. Represent the magnitude and direction of a vector using a protractor and ruler.
2. Multiply or divide a vector quantity by a scalar quantity.
3. Use the methods of graphical analysis to determine the magnitude and direction of the vector resultant in problems involving vector addition or subtraction of two or more vector quantities. The graphical methods to be used are the parallelogram method and the tip to tail method.
4. Use the trigonometric component method to resolve a vector components in the x and y directions.
5. Use the trigonometric component method to determine the vector resultant in problems involving vector addition or subtraction of two or more vector quantities.
6. Use the kinematics equations of Chapter Two along with the vector component method of Chapter Three to solve problems involving two dimensional motion of projectiles.
Links:
Vector Addition & Components
Vector Lab Checklist:
- Each person must turn in a complete lab.
- All work & calculations must be shown for case 1
- A Results summary of all 5 cases
- Discussion Section: Overall results/improvements/ questions
Review:
http://www.physicsclassroom.com/class/vectors/
Will most of these materials be used and explained in the next lab?
ReplyDeletePhysics B is green in the calendar right?
ReplyDeleteYes. We're moving up the ladder of colors. Orange was so last year.
Delete-Kevin Meglathery
We're only green because it's the coolest color in all existence.
ReplyDeleteWhich is a subjective observation and is therefore not capable of being proven.
ReplyDeletewhen finding the magnitude and angle of the unknown vector are we supposed to guess and check with the force table and then check our answer mathematically or are we supposed to find the magnitude and ang to begin with
ReplyDelete-Jaz Popa
DeleteI meant to say or find the magnitude and angle mathematically to begin with
Delete-Jaz
We should probably do the math first. I don't know if all the tables are like this, but the ring on mine doesn't move if you only put on 1 gram (I don't think it's sensitive enough). If you tried guess and check, you might not get the exact answer.
Delete-Kevin Meglathery
Ya that's what I was thinking but I am a little confused about how you would find that. Like what equation do you have to use? -Jaz
DeleteCan someone explain to me how to find the angle required to zero the forces without guessing and checking what puts the ring in like with the center?
ReplyDeleteI found the components of the two given angles. Then I added the x components together and the y components together and the opposite of those are the components of the unknown angle. Then I used tangent to find the angle measure and usually added 180 to it.
DeleteMartin/Jaz/Other confused persons, hopefully this will help:
ReplyDeleteFirst, make sure you have thoroughly read the Force Table Lab.
Make sure to see the note on the bottom of the first page.
You can solve it graphically or algebraically.
Have clear pictures for both methods.
Algebraically, you separate the vectors given into their x and y components:
*Make sure your component vectors match the quadrant of the resultant vector (e.g. if Vector A is Quadrant I, in which both x and y are positive, the component x and y vectors should both be positive)
By identifying the angle given and the side to match it to special right triangle.
OR
By using a trigonometric function (Sine, Cosine or Tangent: [SOHCAHTOA]) to find a second side of the “right triangle of vectors” using the side and angle you know, and the finding the third side using Pythagorean Theorem.
*Be sure to label the direction of each vector when drawing your right triangles, which are composed of your vector (the hypotenuse) and its two component vectors (the legs).
Then, you add the vectors, which in the lab's Case I equal zero.
You solve for the vector you are trying to find (the sum of all the vectors in this case equals zero). Then, using the x and y component values of the vector you found, you use Pythagorean Theorem to find the resultant vector’s magnitude and the Trigonometric Functions to find its direction.
Graphically, you have to add the vectors by drawing them to scale starting from the origin, add them head to tail, and because of the fact that all of Case I's vectors added together equal zero, you can measure the angle and distance from the last vector's head to the end of the first vectors tail (which is the origin). This will give you the direction of the missing vector, and you just have to change the length of the final vector on the picture into the magnitude using your scale (e.g. 1 cm=1 N).
*Be sure to check your answer using a different method and the Force Table.
...Probably forgot to add something............
In other words, make the magnitudes equal to the total net force, 0. Then you solve it like an equation.Once you have the x- and y-components, you work backwards to find the angle and magnitude of vector C. It says it right in the directions:
DeleteFor X-Component
0 = (First magnitude)*cos(first angle) + (Second magnitude)*cos(second angle) + C
For Y-Component
0 = (First magnitude)*sin(first angle) + (Second magnitude)*sin(second angle) + C
In other other words, you find how hard the masses are pulling in a single direction and find the opposite.
Delete-Kevin Meglathery
How do you draw the triangles when the degree measures are 90 and 0 ???
ReplyDeleteThe 0 degree vector will be pointing due East. 90 degrees points due North. If you mark the angles as you would with a unit circle, it should make sense.
Delete-Kevin Meglathery
You dont need to draw triangles. For 90 degrees the x- component is 0 because if you think of the center of the table as zero you are moving straight up from that so your x value isnt changing. Your y-component would equal your magnitude. For 0 degrees it is very similar. Only your y-component is zero and your x-component is the magnitude.
DeleteKara Sulzer
There is no need to draw triangles when the degree measures are 90 and 0. Assuming you are using 0 to 180 and 90 to 270 are your x and y axis, the 90and 0 degree angle will wind up being on the axis. When on the x axis, 0, the vector will only be going in the right direction making the y component 0 and the x component the magnitude of the vector. For the 90 degree vector, it is not going in the x direction at all making the x component 0 and the y component the magnitude of that vector. -Jaz Popa
DeleteHow much of the lab should be completed for tomorrow?
ReplyDelete-Noa L
He never really said but since he wasn't in class on Friday he will probably give us some class time but just incase I would probably do some of it
DeleteKara Sulzer
When it says "multiply or divide a vector quantity by a scalar quantity", what does it mean?
ReplyDeleteKara Sulzer
Vector quantities have direction and scalar don't. So think of meters per second- it's velocity (direction) divided by time (no direction). It's probably so we know that both types can be used together.
Delete-Kevin Meglathery
I remember there being a brief discussion about syncing the blog's Google calendar with our smartphones. Can you provide a tutorial please?
ReplyDeletethe lab isnt due until friday. right?
ReplyDeleteThat is right Kara. -Jaz Popa
DeleteShould the discussion portion of this be typed?
ReplyDelete-Jaz Popa
Can the discussion section be in first person? Or should words like "I" and "my" just never appear anywhere in a lab?
ReplyDelete-Kevin Meglathery
Also, is this a full lab that includes all of the sections such as introduction, procedure and all of that? Or is it just the summary of all five cases plus the discussion section?
Delete-Kevin Meglathery
I think you only need the packet to be completely filled out, all the work for the first case to be shown, a big table displaying all your results, and then a discussion section. I'm almost positive that all you need
DeleteOf course I read this after typing a complete lab.
DeleteOh well, thanks anyway, but I guess I'll just go with what I have.
-Kevin Meglathery
What should we study for this vector quest?
ReplyDelete-Jaz Popa
The objectives and the link provided
DeleteThanks man -Jaz
DeleteDoes the discussion need to be a formally written passage like an abstract? Or can we just bullet our questions and things
ReplyDeleteI think formally, like an abstract, would be the best bet for an A. I suggest avoiding bullets . . . it takes away from the examples and discussion you could make out of the lab. I hope that helped!
DeleteIs the discussion supposed to both summarize and discuss the lab? Or is it just supposed to discuss it?
DeleteIs the results summary just what we wrote in the boxes for all five cases except on one sheet of paper?
ReplyDeleteI have the same question.
Delete