Objective:
Devise a method to determine the relationship between length and time of a swing.
Create and interpret a parent graph for the data
Use this Graph PAPER only "CLICK HERE"
Things to think about.
What shape is the graph? Is it lnear?
- If your data does not agree with the class discussion the lab is easily redone at home find a bob and a length of string and measure the time for ten swings take the Avg. It should be clear that it is not a linear relationship..
- Once you have identified the parent graph construct a daughter graph as discussed in class.
- Follow the rules for analyzing linear graphs find the slope and intercept.
Mr. Crane, do you want us to graph the number of seconds in ten swings, or should we graph that number, but divided by ten? Also how are the axes labeled? Should the length be the x and the time be the y?
ReplyDeleteSydney Portock
Mod 4
Great questions. The purpose of the blog is for you and your fellow students to discuss.
DeleteIm thinking we're supposed to find the time of a single swing, so the number being graphed should be the one divided by 10.
DeleteSo that means it would be more precise, right?
DeleteYes, it would be more precise.
DeleteImagine that you could only count the seconds per swing by whole numbers, and say that one swing took 1 second. This would give you one sig fig.
If ten swings take 10 seconds, you would use the equation 10/10. and would get an answer of 1.0, giving you two sig figs.
-Kevin Meglathery
I set up my graph time by length, y by x. I figured this out by looking at the Easy as Pie graph we did earlier in the year. This helped answer one of the questions I had earlier. How would 10/10 give you 2 sigfigs, if 10 only has one?
Delete10 only has one, but 10. has two. That decimal point makes the zero significant.
Delete-Kevin Meglathery
Why would you be dividing with the decimal if you are only dividing by 10?
DeleteCounting out 1 second is the same as counting "one point." This precision allows you to say that the value is between .5 and 1.4.
DeleteCounting out 10 seconds would be saying "ten point." This precision allows you to say that the value is between 9.5 and 10.4.
The range for both cases is the same, but there are more sig figs in the second one (2 and 3 sig figs versus only 1 and 2).
By counting to an additional place value (going from the ones place to the tens place), you are allowed to use the extra sig fig.
-Kevin Meglathery
That makes a lot of sense. Thanks! I didn't understand it at first, but now it makes so much more sense.
DeleteWhy is the graph so little? and only half of the graph is printing out...help
ReplyDeleteSydnee VanDyke
Mod 4
Does your computer have a setting for print preview? Maybe if you view the graph in print preview it may tell you how to print the whole page and not half?
DeleteIt's still not working, thank you so much of trying, I've created a Frankenstein graph...
DeleteMaybe you can print one out at school tomorrow?
DeleteI think I'll show him my graph during lunch and see what he thinks.
DeleteOkay, that's a good idea.
DeleteAfter finally finishing the graph, I discovered it really isn't linear, but it is very close. Since the correlation is strong and positive it looks almost linear at first glance. However, you are able to draw a BLOF hitting most of the points, just not all of them. Also, should we have figured out the slope and basically set up this graph like the Easy as Pie one?
ReplyDeleteJacob Ludwig Dan Nachtigall A way to get a relation between the length of the string and time of the swings is to take two points on the graph you make and use the slope formula y2-y1 over x2-x1 then it would give you a slope which is the relation between the two amd how they change.
ReplyDeleteTo find the relationship between the length and time of the swings I analyzed the data and observations I had so far. Even though I did not record all of the times per one swing for each different length, the few I do have helped me determine that as the length of the string is shorter, so is the time. This would result in a graph that would have a strong positive correlation, as Sydney said. Though all of the points do not connect to a perfect line, many of the points are extremely close to the line of best fit.
ReplyDeleteChristina Collings
Mod 4
So the time values should be on the y-axis, and the lengths on the x?
ReplyDeleteBeth McNamee Mod 4
I couldn't even get the link to the graph paper to open? It just opened to a blank page?
ReplyDeleteLizzie Peteraf
Mod 4
Dan Nachtigall MOD 7 Mr. Crane I wasn't here on friday, could you or someone explain the 12 graphs of physics?
ReplyDeletewhat exactly do we have to do for the daughter graph again. I am a little confused.
ReplyDeleteJohn McLaughlin mod 4
For the daughter graph you have to graph the time vs. the square root of the lengths of the string.
DeleteSydney Portock Mod 4
i was on vacation for the past week and my wifi was not working. could someone explain the homerwork for me?
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteAfter finishing both graphs, I concluded that as the length of the string gets shorter, the time also gets shorter. Since the slope of the line is positive, the graph has a positive correlation. The majority of the points do fit into the BLOF, but not all.
ReplyDeleteMadison Weiss
Mod 4
I agree with Madison. Just from looking at my points, I could see that both get small as the graph progresses. Also, what is on the y axis?
ReplyDelete- Austin Blumetti MOD4
For the parent graph, time should be on the y axis and length should be on the x axis.
DeleteSydney Portock Mod 4
ok thanks. wb the daughter graph? I wasn't here Friday
ReplyDelete