I got an answer for the wavelength of the red laser, but it seems too small to be correct. Our diffraction square was .48 meters from the whiteboard. The center dot was .08 meters away from the next closest one. The angle between these two spots was about 9.46 degrees. For the distance between the two "slits", we got .000188 meters. When we plug everything into the equation, we got a wavelength of about 310 nanometers. I thought that red light was a much larger wavelength than that, closer to 700 nm. Can anyone see something that I did wrong? -Kevin Meglathery
Mr. Crane remarked that the wavelength we would get from our experiment would not match the standard wavelength for red/green light in our class, that might have some effect.
Physics is the best.,
ReplyDelete"haha, I'm in Physics and you're not! HAHA"
ReplyDeleteI got an answer for the wavelength of the red laser, but it seems too small to be correct. Our diffraction square was .48 meters from the whiteboard. The center dot was .08 meters away from the next closest one. The angle between these two spots was about 9.46 degrees. For the distance between the two "slits", we got .000188 meters. When we plug everything into the equation, we got a wavelength of about 310 nanometers. I thought that red light was a much larger wavelength than that, closer to 700 nm. Can anyone see something that I did wrong?
ReplyDelete-Kevin Meglathery
Mr. Crane remarked that the wavelength we would get from our experiment would not match the standard wavelength for red/green light in our class, that might have some effect.
DeleteMake sure you use .00000376 for d. It's two lines, not one. So all you have to do is what we did in class today, λ=d sinθ
DeleteWhat did i miss in class today?
ReplyDeleteWe began a lab wherein we verify the angle of refraction off water by shooting green laser through a prism with and without water in it
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