Discuss this online via the blog include your first initial last name in the post.
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Why is this graph signicant to the lab?
How is this different than any other WB?
What is the idea that explains the difference?
Sorry did this Friday & it said it posted!
MWeiss
ReplyDeleteThis graph is significant to the lab because it exemplifies a key point: at any direction change in a position vs. time graph, the velocity has to be zero at the time. Velocity is the rate at which an object changes position. In other words, at the point that the car reaches it's maximum position and changes direction, for that short frame of time, the velocity is zero because the car is not changing position at any rate. In this particular experiment, the car started at the bottom of the ramp and was pushed by one of the girls. This is shown in the graph when the parabola starts below zero or negatively. The point in the middle shows the time when the car stood still, or the maximum position of the car, before it began to roll from the top of the ramp (positive) to the bottom of the ramp (negative). In contrast to the other experiments, the girls positioned ULI on the bottom of the ramp, or the negative side. This mad ULI view the top as positive, as shown in the graph. In our group we knew that the curve of our graph was related to the direction in which the car was going in. However, this group took it a step further experimenting with two different directions in one graph
Your observations give a good summary for the basis of our lab. Most importantly, one thing that could be seen throughout all of the graphs was the relationship between the position vs time graphs and the velocity vs time graphs. It is clear that each vertex of the p vs t graph directly relates with a zero of the v vs t graph. Along with this, our graph is able to show that this holds true in more than one instance. Though we flipped our ramp, the vertex still matched up with the zero. However, because our ramp was flipped, the buggy was pulled in a negative direction rather than a positive one. So, the two graphs both ended with negative results.
DeleteMWeiss
ReplyDeleteIn the velocity vs. time graph, the velocity starts out positive. It's a linear graph that eventually goes below zero into the negatives. The acceleration, or slope of a velocity vs. time graph is constant. The point at which the line crosses through zero corresponds to the point in the pos. vs. time graph when the car reached it's maximum position, before rolling back down.
This graph is significant because this is the first time I saw the ULI being placed at the bottom of the ramp instead of the top, making ULI see the top as a positive direction. They also showed the car going two different ways which was also something I didn't think of.
ReplyDeleteE. Hudson
This experiment is very similar to the experiments done by 2 other groups, Zach's and Jenny's I think? They all started the car at the bottom of the ramp and tried to make it go up, which due to gravity eventually fell back down. The only difference is that ULI was positioned at the bottom of the ramp for this lab instead of the top. They all had a parabola for the position vs. time graph, and a straight line for the velocity vs. time, depending on the part of the graph which is being shown. The significant differences are that the parabola for this one is upside down, and the slope for the velocity vs. time is negative instead of positive. These results make sense since everything in the experiment was just made opposite due to the placement of ULI.
ReplyDeleteM. McNamee
John McLaughlin-
ReplyDeleteIn this experiment we see that the ULI is put at the bottom of the ramp instead of being at the top. This can completely change the way the data looks. They're Velocity vs. Time graph reads that the buggy starts at a positive velocity and over time, decreases. For the Position vs. Time Graph, they have a parabola. A difference I saw is that the parabola is upside down. This graph is showing that the buggy starts at a negative position, moves to a positive position, then moves back to a negative position. This is shown in the actual lab by the buggy moving up the ramp and then back down.This data does make sense due to the fact that they changed ULI's position from the top, to the bottom of the ramp.
S. Portock
DeleteThe velocity of the car does not necessarily decrease. The velocity is just negative because of the changing position of the car.
This graph shows both similarities and differences to other graphs. All of the graphs show constant velocities at one point or another in their velocity vs time graphs. However, the velocity is negative rather than positive. The parabola is also upside down compared to others we saw in class. This was due to where ULI was placed. Usually ULI was at the top of the ramp. In this one ULI was at the bottom so that the car was going up the ramp and away, and then back down and towards. This changed the direction of the parabola. This did not change how the car lost velocity at the turning point. this is shown in other graphs as well.
ReplyDeleteA Berg
E. Hoffman
ReplyDeleteThis graph displays data that shows that Juli was placed on the bottom of the ramp instead of on top like the original experiment. This graph is significant because it shows the difference from when Juli is on top of the ramp compared to on the bottom. The car went in both directions in this scenario because of gravity. The car went up the ramp and then had a velocity of zero before coming back down. Therefore, Juli picked up a negative and then a positive velocity which indicates the direction change. The position vs. time graph shows the car getting closer to the motion detector but then getting farther away which is also a key point.
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ReplyDeleteThese graphs are a great demonstration of the difference between a position v. time and a velocity v. time graph. It compares the affects of both the positive and negative velocity of the car that is being recorded on the different graphs. While the velocity graph is linear, the position graph is exponential. This is because a velocity graph's slope would be (m/s)/s, but a position graphs slope is simply m/s. Another interesting detail this graph contains is that the parabola's vertex on the position graph occurs at the same time the velocity graph is at its x- intercept and x values are going from positive to negative. This is because at that moment the car's velocity decreases until it completely stops and eventually starts to roll back down the incline. ULI's position at the bottom makes it so this change is negative. The car is also able to go into the negative positions due to ULI's zero being set in the ramps middle rather than at ULI itself. At the different actions of the car and ULI affect both the position and velocity graphs in different yet relating ways.
ReplyDeleteLarry Strenger
I noticed immediately by looking at this group's graph data that it is the exact opposite of the data which Zach's group collected. This would make perfect sense because ULI's frame of reference has been reversed. Instead of seeing the bottom of the ramp as positive and the top of the ramp negative, position wise, it now sees it in the opposite way. This makes this data significant because it shows the importance of ULI's frame of reference. Even though the car followed the exact same path in both runs, the graphs at first glance look very different from those of Zach's group. This run was also different from any of the others because all of the other ones discussed in class had ULI positioned at the top of the ramp looking down, but once again, this one had ULI looking up at the car from the bottom of the ramp, therefore reversing its positive and negative position and velocity measurements.
ReplyDeleteS. Portock
DeleteI agree with you. our graph is the reverse of most of the other graphs. We noticed that when we let go of the car at any position, negative or positive, it would always move away from ULI and make a parabola. So we changed this aspect of the experiment. Things that.
E Pushman
ReplyDeleteThis graph is significant to the lab because ULI was placed at the bottom of the ramp. In all the other tests i saw ULI was at the top of the ramp. This changes the way the graph looks. In the Position vs Time graph the graph is an upside down parabola. The buggy started off in a negative position, moved to a positive position, then back down into a negative position. This is the opposite of what i did in my test. The slope of the Velocity vs Time graph is constant and negative. The slope starts out positive and constantly decreases. The Velocity hits zero when the object changes direction. This shows us that when there is a change in direction, the velocity is zero. It was important that they did their graph different then us because it showed how the graph would look different if ULI was at the bottom of the ramp instead of the top.
My group did an experiment similar to this one, only we only sent the buggy towards ULI, not away and then towards. When we first began the lab, we identified items that could be changed. The cars direction towards ULI was one of them. When we ran the buggy away from ULI, the parabola opened upwards; when we ran the buggy towards ULI, the parabola opened downwards. The significance or key idea of this lab is that the way the parabola opens is related to the direction you send the car (towards or away from ULI). In the P v T graph above, we see the graph reach a max, at the max the slope--or in this case velocity is 0. In the V v T graph above, the slope is still linear therefore the car still accelerated at a constant rate.
ReplyDeleteThis graph is significant to the lab because it shows the main ideas that the lab was trying to teach. It shows that while the position vs. time graph is quadratic, the velocity vs. time graph is linear and has a constant slope. Also, shows how the frame of reference changes the graphs. Because 0 is set at the middle of the ramp and not at ULI itself, the position vs. time graph is able to go from negative to positive and back again. This graph is almost an exact reflection of the graphs that my group got. Our position vs. time graph had a parabola that faced upward while this parabola faces downward. In addition, our velocity vs. time graph had a positive slope, but this one has a negative slope. The factor that caused this difference was the placement of ULI. We placed ULI at the top of the ramp, and this group placed ULI at the bottom of the ramp. This changed the frame of reference and caused the graphs to be opposites of each other.
ReplyDelete-Jacob Anapolle
C. Collings
ReplyDeleteThis graph is significant to the lab because it shows a key idea. The idea shown is that in a position vs. time graph, the change in direction will have a velocity of zero. The maximums or minimums show the change in direction from that particular point, when the velocity is increasing (in this case) in either direction. This is important to the lab because as a class, we have not discussed what the maximums and minimums of the position vs. time graphs meant, and without identifying all aspects of each graph, we would not know how to properly analyze them. The difference between this experiment and the others on the whiteboards is that ULI is placed at the bottom of the ramp so that the car starts out in a positive direction but then falls as it reaches its maximum towards the top of the ramp. Previously, the graphs we have analyzed only focused on the car going in one particular direction; however, this experiment touched on both ways. The idea that explains this difference is how in the other analyzed graphs there was only half of a parabola, showing the car moving in only one direction. This experiment shows a full parabola, clearly expressing the change in direction, including the car’s maximums and minimums. A similarity between this experiment and previous ones is that the velocity vs. time graph is linear, constant, and increasing (in this case, in a negative direction.)
This graph is significant because it shows that the ULI is placed at the bottom of the graph instead of the top like usual. This alternates which direction is positive and which direction is negative. Also the graph depicts that the car changed direction at one point.
ReplyDeleteA. Shafi
M. Hasan
ReplyDeleteThese graphs are significant to the lab because it compares position v. time graph and the velocity v. time graph. ULI was placed on the bottom of the ramp. When the car was coming toward ULI the position became negative and the other way around. Since they sent the buggy up the ramp first and then let it come down it created a parabola. The m was constant, changing, and negative. The starting velocity was positive and then it changed to negative because the ULI was placed at the bottom of the ramp. The m was constant and changing negative just like the position v time graph. Since they put the ULI at the bottom of the ramp it changed the frame of reference.
Dan Nachtigall Mod 7 Mr. Crane check this out http://m.bbc.com/news/science-environment-26605974
ReplyDeleteMadison Weiss
ReplyDeleteMod 4
I was doing the Stacks of Kinematic Curves ws and I graphed the acceleration for problem one as constant and positive, a straight line. I was wondering if in the motion map it that would be represented as just vectors in a straight line that have the same size, since the acceleration is constant? Does it matter what direction the arrows are pointing?
Also, should the motion map show the velocity vs time graph and the acceleration vs. time graph?
ReplyDelete